# Project Euler Problem #1 Solution in Java

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

Solution in Java:

package problem1;

/**

* @author Khuram Ali

*/

public class Problem1

{

public static void main(String[] args)

{

int maxNum = 1000;

int result = 0;

for (int i = 2; i < maxNum; i++)

{

if (i % 5 == 0)

{

result += i;

}else if (i % 3 == 0)

{

result += i;

}

}

System.out.println (“total of multiples of 3 or 5: “) ;

System.out.println (result);

}

}

Posted on March 26, 2013, in Java, Project Euler and tagged Java, Programming, Project Euler solution in Java. Bookmark the permalink. 2 Comments.

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