Project Euler Problem #1 Solution in Java

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

Solution in Java:

package problem1;
/**
* @author Khuram Ali
*/
public class Problem1
{

public static void main(String[] args)
{
int maxNum = 1000;
int result = 0;

for (int i = 2; i < maxNum; i++)
{
if (i % 5 == 0)
{
result += i;
}else if (i % 3 == 0)
{
result += i;
}
}
System.out.println (“total of multiples of 3 or 5: “) ;
System.out.println (result);
}
}

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About Khuram Ali

Programming... Programming and Programming...!!!

Posted on March 26, 2013, in Java, Project Euler and tagged , , . Bookmark the permalink. 2 Comments.

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