Project Euler: Problem #1 solution in C++

/**(From:http://projecteuler.net/index.php?section=problems&id=1)

Problem Description:
If we list all the natural numbers below 10 that are multiples of 3 or 5,
we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.

Solution:*/

#include <iostream>

using namespace std;

int main ()
{
int maxNum = 0;
int result = 0;

cout << “Please enter max number limit for the sum of all the multiples of 3 or 5: “;
cin >> maxNum;

for (int i = 2; i < maxNum; i++)
{
if (i % 5 == 0)
{
result += i;
}else if (i % 3 == 0)
{
result += i;
}
}
cout << “total of multiples of 3 or 5: ” << result << endl;

}

Advertisements

About Khuram Ali

Programming... Programming and Programming...!!!

Posted on March 25, 2013, in Algorithms, C++, Programming, Project Euler and tagged . Bookmark the permalink. 2 Comments.

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s

%d bloggers like this: