# Project Euler: Problem #1 solution in C++

`/**(From:http://projecteuler.net/index.php?section=problems&id=1)`

`Problem Description:`

If we list all the natural numbers below 10 that are multiples of 3 or 5,

we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

Solution:*/

#include <iostream>

using namespace std;

int main ()

{

int maxNum = 0;

int result = 0;

cout << “Please enter max number limit for the sum of all the multiples of 3 or 5: “;

cin >> maxNum;

for (int i = 2; i < maxNum; i++)

{

if (i % 5 == 0)

{

result += i;

}else if (i % 3 == 0)

{

result += i;

}

}

cout << “total of multiples of 3 or 5: ” << result << endl;

}

Posted on March 25, 2013, in Algorithms, C++, Programming, Project Euler and tagged Project Euler solution in C++. Bookmark the permalink. 2 Comments.

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